(3x^2-2x+1)(x^2-8)=

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Solution for (3x^2-2x+1)(x^2-8)= equation: 


Simplifying
(3x2 + -2x + 1)(x2 + -8) = 0

Reorder the terms:
(1 + -2x + 3x2)(x2 + -8) = 0

Reorder the terms:
(1 + -2x + 3x2)(-8 + x2) = 0

Multiply (1 + -2x + 3x2) * (-8 + x2)
(1(-8 + x2) + -2x * (-8 + x2) + 3x2 * (-8 + x2)) = 0
((-8 * 1 + x2 * 1) + -2x * (-8 + x2) + 3x2 * (-8 + x2)) = 0
((-8 + 1x2) + -2x * (-8 + x2) + 3x2 * (-8 + x2)) = 0
(-8 + 1x2 + (-8 * -2x + x2 * -2x) + 3x2 * (-8 + x2)) = 0
(-8 + 1x2 + (16x + -2x3) + 3x2 * (-8 + x2)) = 0
(-8 + 1x2 + 16x + -2x3 + (-8 * 3x2 + x2 * 3x2)) = 0
(-8 + 1x2 + 16x + -2x3 + (-24x2 + 3x4)) = 0

Reorder the terms:
(-8 + 16x + 1x2 + -24x2 + -2x3 + 3x4) = 0

Combine like terms: 1x2 + -24x2 = -23x2
(-8 + 16x + -23x2 + -2x3 + 3x4) = 0

Solving
-8 + 16x + -23x2 + -2x3 + 3x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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